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- >Equation involving roots.
- x-P∞^≤±x±-1=0
- MYSZEK 2xy
- 121397
- #
- ò
- 21
- We solve an equation involving roots.
-
- Notice the way in which the auxiliary variable is introduced (using the
- arrow, CTRL+=) in steps 1 and 2. When we use it again (in step 3) we use
- the equality sign =.
-
- Step 4. If the equation has more than one solution, we write them using the
- connective OR. Of course we could break down the problem into cases
- (SHIFT+y) and enter each solution separately.
-
- Step 5. We have gone back to the old variables and broken down the problem into
- cases.
-
- Case 2 is a contradiction, so after the answer is given it will be reduced
- to an icon.
-
- In Case 1 the remainder of the solution is left to the user.
-
- By clicking on the tabs at the top we can see all the transformations
- we have carried out. Because not all the tabs fit in the window,
- you have to scroll from time to time by clicking on the arrows on a level with the tabs.
-
- ê
- "
- q¨P∞^≤±x±Éä
- 4
- 4
- Ä™¨1+4ä
- 7
- 7
- ã
- 0
- 0
- 0
- ÜÑx-P∞^≤±x±-1=0Éä
- 12
- 4
- ã
- 0
- 0
- 0
- øq¨P∞^≤±x±ä
- 7
- 4
- Äq^2≤-q-1=0Éä
- 10
- 8
- ã
- 0
- 0
- 0
- øq^2≤-q-1=0ä
- 10
- 4
- Ä™¨1+4Éä
- 7
- 7
- ã
- 0
- 0
- 0
- øq^2≤-q-1=0ä
- 10
- 4
- Ä™=5Éä
- 5
- 7
- ã
- 0
- 0
- 0
- øq=/Ø1+P∞^≤±5±±≤2±⁄q=/Ø1-P∞^≤±5±±≤2±Éä
- 17
- 4
- ã
- 0
- 0
- 0
- øP∞^≤±x±=/Ø1+P∞^≤±5±±≤2±⁄P∞^≤±x±=/Ø1-P∞^≤±5±±≤2±Éä
- 19
- 5
- ã
- 0
- 0
- 0
- øP∞^≤±x±=/Ø1+P∞^≤±5±±≤2±Éä
- 15
- 5
- ã
- 0
- 0
- 0
- ÜP∞^≤±x±=/Ø1-P∞^≤±5±±≤2±Éä
- 2
- 5
- ã
- 0
- 0
- 0
- øx=(/Ø1+P∞^≤±5±±≤2±)^2≤Éä
- 15
- 5
- ã
- 0
- 0
- 0
- øx=(/Ø1+P∞^≤±5±±≤2±)^2≤Éä
- 15
- 5
- ã
- 0
- 0
- 0
- åçP∞^≤±x±=/Ø1-P∞^≤±5±±≤2±Éä
- 2
- 5
- ã
- 0
- 0
- 0
- ñàçé
- 0
- 0
- 0
- 9
- 1
- 5
- 0
- 0
- è
-